Errata for Henderson/Taimina, Experiencing Geometry (3rd edition)
Changes in Red.
pg xix, line 23: “George_Lobell@prenhall.com or calling 1-201-236-7407.” should be changed to “Nicole_Kunzmann@prenhall.com or calling 1-201-236-7739.”
pg 13, line 12-:
out using its center. When the lengths g and f are equal, then Q draws the
pg 106, equation in Part c-:
replace "(n - 1)" with "(n - 2)"
pg 114, line 11:
any transversal passing through the midpoint of the segment of l
pg 115, line 18:
2. Parallel lines are lines such that every transversal cuts them at
pg 134, Figure 10.6: Remove the three d’s along the bottom of the figure (leave the three d’s near the top.
pg 147, line 2-: this one is not important
some students have affectionately called them “horrorcycles.”] Note that
pg 181, line 4-:
which we will prove in Problem 15.1a, but the special case we need is
pg 196, line 2:
use that result to show that ac = bd or, in equivalent form, a/d = b/c.
pg 198, line 8:
need properties of similar triangles that are investigated in Problem 13.4.
pg 259, Figure 18.15:
Switch the direction of both sides of the octagon that are marked with four arrows.
pg 271, line2 (just below Figure 19.3):
This leads to x
= b/2 − .
Note that if c > (b/2)2, this geometric
pg 387: Remove “59, ” from the
“Gauss” entry, which should now read:
Gauss, 103, 140, 142, 226, 347
pg 390: Poincaré, 258, 354
Conjecture, 257-8
disk model. 212, 234, 242-3
projective disk model, 234, 244
Errata for Henderson/Taimina, Experiencing Geometry (3rd edition)
Instructor’s Manual
Changes in Red.
pg 13, Figure 7: The points C, P, and D should be labeled as follows:
The piont "C" is where the two links of length s intersect.
The point "P" is where the link of length f intersects two links of length d.
The point "D" is the other end of the link of length f.
pg 93, equation in Part c-:
replace "(n - 1)" with "(n - 2)"
pg 106, line 3:
they are also parallel transports along any transversal passing through the midpoint of the
pg 108, line 13:
2. Parallel lines are lines such that every transversal cuts them at congruent angles: or
pg 138, at the end of the first paragraph add:
Draw in the two diagonals and first use SAS and then SSS.
pg 147, Figure 10.6: Remove the three d’s along the bottom of the figure (leave the three d’s near the top.
pg 159, line 2: this one is not important
called them “horrorcycles.”] Note that on the plane circles of infinite radius are straight lines.
pg 201, line 8:
that we will prove in Problem 15.1a, but the special case we need is easy to see now. In particular
pg 213, last five lines:
Now, if θ = π/2, then the above equal areas are the products ac = bd, and cross-dividing we
get the desired a/d = b/c. Then we can define the usual trigonometric functions for right
triangles. For arbitrary θ the above equal areas are ac sinθ = bd sinθ, so again cross-dividing, we
get:
a/d=b/c.
pg 215, line 5-:
triangles that are investigated in Problem 13.4.
pg 275, Figure 18.15: Switch the direction of both sides of the octagon that are marked with four arrows.
pg 287, line 1 (just below Figure 19.3):
This leads to x = b/2 − .
Note that if c > (b/2)2, then this geometric
solution is impossi-